On Thu, Aug 8, 2019 at 4:23 PM 'Brent Meeker' via Everything List <
[email protected]> wrote:

>
>
> On 8/8/2019 2:03 PM, Jason Resch wrote:
>
>
>
> On Thu, Aug 8, 2019 at 3:48 PM 'Brent Meeker' via Everything List <
> [email protected]> wrote:
>
>>
>>
>> On 8/8/2019 11:50 AM, Jason Resch wrote:
>>
>>
>>
>> On Thu, Aug 8, 2019 at 11:41 AM 'Brent Meeker' via Everything List <
>> [email protected]> wrote:
>>
>>>
>>>
>>> On 8/8/2019 1:42 AM, Bruno Marchal wrote:
>>> >> Do you not see that there is only one intermediate state  and the
>>> >> superposition is an artifact of expressing the state relative to a
>>> >> certain basis?
>>> >
>>> > If it was an artfifact, one photon would not been able to interfere
>>> > with itself, and there would be no Bell’s violation.
>>>
>>> It's an artifact of expressing the photon as a superposition of two
>>> bases |left slit> and |right slit> which are not orthogonal. There is
>>> still only one state, one wave function.
>>>
>>>
>> Any multitude of things can also also be viewed as a single collection of
>> that multitude.
>>
>> A multitude of classical computational traces can be found in a quantum
>> computation.  You point out this multitude of computation traces can be
>> viewed as one state of a larger space.  Viewing it this way, however,
>> doesn't eliminate the multitude of the classical computational traces.
>>
>>
>> To call them classical traces implies that they are not coherent and
>> cannot interfere; yet their interference is an essential factor in the
>> computation.
>>
>
> As I've said already, whether or not the coherence is exploited by the
> quantum computer is algorithm-dependent.
>
>
> If it doesn't exploit coherence, is it really doing quantum computation?
>
>
That's a question for you I suppose.  What is it that distinguishes a
classical computation with a single (non-superposed) input on a quantum
computer from a classical computation on a quantum computer?  The only
distinction as I see it is the quantum computer remains isolated from the
environment.

The quantum computer also has the capacity to operate on inputs in a
superposition, representing a vast number of inputs, and the computation
then becomes a superposition of a trace of many classical computations, and
eventually a superposition of possible outputs, at least until measured.

>
> You agree there are the many states in Shor's algorithm before the Fourier
> transform, right?
> Then what happens to those many states if you skip the Fourier transform
> (don't use the interference), you still would say there were many states,
> do you not?
>
>
> No, it's an isolated system going through coherent evolution.  To say
> there are many states is just to choose an arbitrary set of basis and
> vectors and call each component a "state".  There's only one state.
>

LOL it's like pulling teeth.  What word should we use to refer to the "vast
number" or the "them" of your previous e-mails?  Let's agree on that word
and just stick to it rather than go back and forth on terminology.

Jason

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