On 8/8/2019 2:32 PM, Jason Resch wrote:
On Thu, Aug 8, 2019 at 4:23 PM 'Brent Meeker' via Everything List
<[email protected]
<mailto:[email protected]>> wrote:
On 8/8/2019 2:03 PM, Jason Resch wrote:
On Thu, Aug 8, 2019 at 3:48 PM 'Brent Meeker' via Everything List
<[email protected]
<mailto:[email protected]>> wrote:
On 8/8/2019 11:50 AM, Jason Resch wrote:
On Thu, Aug 8, 2019 at 11:41 AM 'Brent Meeker' via
Everything List <[email protected]
<mailto:[email protected]>> wrote:
On 8/8/2019 1:42 AM, Bruno Marchal wrote:
>> Do you not see that there is only one intermediate
state and the
>> superposition is an artifact of expressing the state
relative to a
>> certain basis?
>
> If it was an artfifact, one photon would not been able
to interfere
> with itself, and there would be no Bell’s violation.
It's an artifact of expressing the photon as a
superposition of two
bases |left slit> and |right slit> which are not
orthogonal. There is
still only one state, one wave function.
Any multitude of things can also also be viewed as a single
collection of that multitude.
A multitude of classical computational traces can be found
in a quantum computation. You point out this multitude of
computation traces can be viewed as one state of a larger
space. Viewing it this way, however, doesn't eliminate the
multitude of the classical computational traces.
To call them classical traces implies that they are not
coherent and cannot interfere; yet their interference is an
essential factor in the computation.
As I've said already, whether or not the coherence is exploited
by the quantum computer is algorithm-dependent.
If it doesn't exploit coherence, is it really doing quantum
computation?
That's a question for you I suppose. What is it that distinguishes a
classical computation with a single (non-superposed) input on a
quantum computer from a classical computation on a quantum computer?
The only distinction as I see it is the quantum computer remains
isolated from the environment.
The quantum computer also has the capacity to operate on inputs in a
superposition, representing a vast number of inputs, and the
computation then becomes a superposition of a trace of many classical
computations, and eventually a superposition of possible outputs, at
least until measured.
You agree there are the many states in Shor's algorithm before
the Fourier transform, right?
Then what happens to those many states if you skip the Fourier
transform (don't use the interference), you still would say there
were many states, do you not?
No, it's an isolated system going through coherent evolution. To
say there are many states is just to choose an arbitrary set of
basis and vectors and call each component a "state". There's only
one state.
LOL it's like pulling teeth. What word should we use to refer to the
"vast number" or the "them" of your previous e-mails?
Where did I refer to a "vast number of states"? I have consistently
said there is only one state. The vast numbers are just components of
the state vector which appear because you choose a particular basis.
Just like the x-polarized sliver atom has two components in the y-axis
basis. It doesn't have two states.
Brent
Let's agree on that word and just stick to it rather than go back and
forth on terminology.
Jason
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