On Tuesday, November 12, 2019 at 1:43:56 PM UTC-7, smitra wrote:
>
> On 12-11-2019 01:02, Alan Grayson wrote: 
> > On Monday, November 11, 2019 at 3:40:04 PM UTC-7, smitra wrote: 
> > 
> >> On 11-11-2019 22:44, Alan Grayson wrote: 
> >>> On Monday, November 11, 2019 at 4:35:13 AM UTC-7, Bruce wrote: 
> >>> 
> >>>> On Mon, Nov 11, 2019 at 8:37 PM Bruno Marchal <[email protected]> 
> >>>> wrote: 
> >>>> 
> >>>>> On 10 Nov 2019, at 20:01, Alan Grayson <[email protected]> 
> >>>>> wrote: 
> >>>> 
> >>>> On Sunday, November 10, 2019 at 5:42:50 AM UTC-7, Bruno Marchal 
> >>>> wrote: 
> >>>> 
> >>>> Once the cat is alive + dead, he remains in that state for ever. 
> >>>> 
> >>>> THEN HOW COME WE NEVER OBSERVE THAT STATE? AG 
> >>> 
> >>> Because the observable are defined by their possible definite 
> >> outcome, 
> >>> and for reason already explained, macroscopic superposition 
> >> decoder, 
> >>> that is get entangled with the environment at a very high speed. 
> >> So, 
> >>> if you look at the cat in the a+d state, you are duplicate almost 
> >>> immediately into a guy seeing the cat alive + the guy seeing the 
> >> cat 
> >>> dead, and QM explained why they cannot interact, although they 
> >> might 
> >>> interfere themselves. 
> >>> 
> >>> That is exactly a preferred basis -- which you seem to want to 
> >> deny. 
> >>> 
> >>> Bruce 
> >>> 
> >>> In the case of a radioactive atom in state |decayed> + 
> >> |undecayed>, 
> >>> what's the justification and advantage of the interpretation that 
> >> it's 
> >>> in both states simultaneously? AG 
> >> 
> >> This is what happens, as confirmed by experiment. In case the decay 
> >> happens fast and there is more than one decay channel, the decay 
> >> will 
> >> happen to a superposition of the different possibilities. It's then 
> >> not 
> >> a decay to one of the possibilities and we just don't know which 
> >> one. 
> >> The difference between the two scenarios has in principle 
> >> experimentally 
> >> verifiable consequences.  For example, the Delta++ particle decays 
> >> to a 
> >> proton and a positive pion due to the strong interaction. The strong 
> >> 
> >> interaction obeys isospin symmetry. From this one can deduce by 
> >> applying 
> >> a rotation in isospin space that the delta+ particle should decay to 
> >> the 
> >> superposition sqrt(1/3)|n>|pi+> + sqrt(2/3)|p>|pi0> where |n> 
> >> denotes a 
> >> neutron|p> a proton and |pi0> and |pi+> are neutral and positive 
> >> pions. 
> >> Experiments have confirmed the relative decay probabilities of 1/3 
> >> and 
> >> 2/3. 
> >> 
> >> Saibal 
> > 
> > I don't see how this relates to my question. If the relative decay 
> > probabilites 
> > are what you state, does this mean that the system PRIOR to decay is 
> > several different states simultaneously? AG 
>
> The system will in general be in a superposition, this follows from the 
> Schrodinger equation. The fact that a decay can happen at all means that 
> the particle states are not eigenstates of the full Hamiltonian. If you 
> consider a decay in a fixed volume and you impose reflecting boundary 
> conditions, then you won't get a permanent decay at all. The 
> superposition will end up oscillating back and forth from the original 
> particle to the decay products and back. When we compute the decay rate 
> in QM we need to take the limit to an infinite volume to eliminate this 
> oscillation effect and make the long term decay visible. But in 
> principle the superposition between the original undecayed particle and 
> the decay products will always continue to exist. 
>
> Saibal 
>

Thanks, but the issue I am raising is not whether a superposition continues 
to
exist, but the proper interpretation of it. For example, can a radioactive 
source
be decayed and undecayed simultaneously, or is Philip correct in claiming 
both
states are simultaneous possibilties? Huge difference. AG 

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