> On 12 Nov 2019, at 22:06, Alan Grayson <[email protected]> wrote: > > > > On Tuesday, November 12, 2019 at 12:14:26 PM UTC-7, Philip Thrift wrote: > > > On Tuesday, November 12, 2019 at 8:28:22 AM UTC-6, Alan Grayson wrote: > > > On Tuesday, November 12, 2019 at 1:24:44 AM UTC-7, Philip Thrift wrote: > > > On Monday, November 11, 2019 at 5:58:30 PM UTC-6, Alan Grayson wrote: > > > On Monday, November 11, 2019 at 2:52:25 PM UTC-7, Philip Thrift wrote: > > > On Monday, November 11, 2019 at 3:44:24 PM UTC-6, Alan Grayson wrote: > > In the case of a radioactive atom in state |decayed> + |undecayed>, what's > the justification and advantage of the interpretation that it's in both > states simultaneously? AG > > None, since it isn't. > > @philipthrift > > But doesn't the either/or situation imply no interference? AG > > In the case of radium atom decay or no-decay which kills or doesn't kill the > cat, there is no interference of the two possible histories (as I understand > what physically is going on). Only one history survives. > > @philipthrift > > Forget about the cat. For the radioactive source, can it ever be decayed and > undecayed simultaneously, and if so, why? AG > > > No. > > It can "be" possibly-decayed and possibly-undecayed simultaneously. > > That's as much as we can model the quantum nature of it. > > @philipthrift > > I think that's the statistical interpretation of the wf.
It seems to me that it is more like Popper’s propensity interpretation. But it makes not much sense. If the observer is described by the wave, and obey to Mechanism, he will not been able to see the difference between belonging to a possibility or an actuality, so Popper need a non computationalist theory of mind, which indeed he developed with Eccles, but it is hardly convincing, Imo. Bruno > Doesn't that imply there is no interference? AG > > -- > You received this message because you are subscribed to the Google Groups > "Everything List" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected] > <mailto:[email protected]>. > To view this discussion on the web visit > https://groups.google.com/d/msgid/everything-list/6ffddf8e-ebf2-4191-a32e-5f549691a6e0%40googlegroups.com > > <https://groups.google.com/d/msgid/everything-list/6ffddf8e-ebf2-4191-a32e-5f549691a6e0%40googlegroups.com?utm_medium=email&utm_source=footer>. -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/everything-list/75E882C6-07DA-4A9A-A5A6-A5981F170E2A%40ulb.ac.be.
