On Sunday, July 4, 2021 at 1:51:51 PM UTC+2 Bruce wrote: > > And in the two-outcome experiment, how do you ever get a probability > different from 0.5 for each possible outcome? > > You would seem to be looking for a branch counting explanation of > probability (self-locating uncertainty). But there is no mechanism in > Everett or the Schrodinger equation to give anything other than a 50/50 > split when only two outcomes are possible. This is wildly at variance with > experience. >
In the classical example with balls you may have a collection of blue and red balls so there are only two possible outcomes of a random selection of a ball: blue and red. This doesn't mean that the proportion of blue and red balls in the collection must be 50/50. Why would the proportion of branching worlds necessarily be 50/50 if there are only two possible outcomes? -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/everything-list/2269f8ff-0d6d-406d-b559-68aa1c5bf90en%40googlegroups.com.
