On Sun, Jul 4, 2021, 6:54 PM 'Brent Meeker' via Everything List < [email protected]> wrote:
> > On 7/4/2021 5:17 AM, Tomas Pales wrote: > > > On Sunday, July 4, 2021 at 1:51:51 PM UTC+2 Bruce wrote: > >> >> And in the two-outcome experiment, how do you ever get a probability >> different from 0.5 for each possible outcome? >> >> You would seem to be looking for a branch counting explanation of >> probability (self-locating uncertainty). But there is no mechanism in >> Everett or the Schrodinger equation to give anything other than a 50/50 >> split when only two outcomes are possible. This is wildly at variance with >> experience. >> > > In the classical example with balls you may have a collection of blue and > red balls so there are only two possible outcomes of a random selection of > a ball: blue and red. This doesn't mean that the proportion of blue and red > balls in the collection must be 50/50. Why would the proportion of > branching worlds necessarily be 50/50 if there are only two possible > outcomes? > > > It's not that it's necessarily 50/50; it's that there's no mechanism for > it being the values in the Schroedinger equation. In one world A happens. > In the other world B happens. How does, for example, a 16:9 ratio get > implemented. There's nothing in Schroedinger's equation that assigns one > of those numbers to one world or the other. You can just make it an > axiom. Or equivalently, if you can show these are odds ratios, you can > invoke Gleason's theorem as the only consistent probability measure. But > all that is extra stuff that MWI claims to avoid by just being pure > Schroedinger equation evolution. > > Brent > > Is this question unique to MW? Do Copenhagen/GRW/QBism/Transactional/Bohm have any advantage(s) in explaining the Born rule? I don't understand the problem that's unique to MW. Jason > > -- > You received this message because you are subscribed to the Google Groups > "Everything List" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > To view this discussion on the web visit > https://groups.google.com/d/msgid/everything-list/44aceed9-5408-9dc0-ebcb-436765a7df23%40verizon.net > <https://groups.google.com/d/msgid/everything-list/44aceed9-5408-9dc0-ebcb-436765a7df23%40verizon.net?utm_medium=email&utm_source=footer> > . > -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/everything-list/CA%2BBCJUjA7u%2BF7R4qhjby%2BcBBYBZ2kirPCfTV6-oYk8tQf%2Bs6Lw%40mail.gmail.com.
