Le jeu. 13 févr. 2025, 09:42, Bruce Kellett <bhkellet...@gmail.com> a
écrit :

> On Thu, Feb 13, 2025 at 6:30 PM Quentin Anciaux <allco...@gmail.com>
> wrote:
>
>> Bruce,
>>
>> Listing 2^N sequences does not prove that measure is irrelevant. Yes, all
>> sequences exist, but that does not mean they all contribute equally to an
>> observer’s experience. Your argument assumes that each sequence corresponds
>> to exactly one branch with exactly one observer, but nothing in unitary
>> evolution enforces such a strict partitioning.
>>
>> Branches are not necessarily discrete, isolated entities—they could
>> always remain in a superposition of infinite sub-branches, with measure
>> determining the relative weight of each. If measure partitions reality
>> rather than simply labeling sequences, then high-measure branches dominate
>> experience, naturally leading to the Born rule.
>>
>> Your argument assumes its conclusion: that each sequence corresponds to
>> one and only one branch, with no role for measure. But you haven’t proven
>> this—just asserted it.
>>
>
> You are simply ignoring the case I made. This discussion will not go
> anywhere as long as you don't listen.
>
> Bruce
>

Ok then let's leave it at that, surely I'm too stupid, no problem.

Quentin


> The fact is that you get the same 2^N binary sequences from the binary
> state |psi> = a|0> + b|1> whatever the values of a and b. My case is proven.
>
> Bruce
>
>
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