Bruce, Your assertion is absurd. The existence of 2^N sequences is not in question—it's a direct prediction of MWI. The issue is whether all sequences contribute equally to probability, which they demonstrably do not, as experiments confirm the Born rule, not a uniform distribution.
I’ve already provided multiple counterexamples—the lottery analogy, asymmetric duplication, and multiple instances of a conscious program—all illustrating why raw sequence count is irrelevant without considering measure. Amplitudes are fundamental in the Schrödinger equation, and treating them as meaningless contradicts everything we know about quantum mechanics. If you believe you’ve disproven MWI, publish it. Otherwise, all you’re doing is repeating claims without engaging with their refutation. Quentin Le dim. 23 févr. 2025, 23:22, Bruce Kellett <bhkellet...@gmail.com> a écrit : > On Mon, Feb 24, 2025 at 9:00 AM Quentin Anciaux <allco...@gmail.com> > wrote: > >> Bruce, you keep insisting that unitary QM provides no mechanism for >> measure affecting observer distribution, but you haven't actually proven >> this—only asserted it. >> > > You have not proven the contrary. It is all merely assertion on your part. > If you are so convinced that unitary evolution can produce the structures > you envisage, then derive those structures with the context of unitary QM. > Show the mathematics! > > All that is required to prove my point is to observer that the 2^N binary > sequences that result from repeated measurements of the simple binary state > a|0> + b|1> do not depend on the amplitudes a and b. If you dispute this, > show how the binary sequences do depend on the amplitudes. Don't just > assert it. What different set of sequences do I get with differing values > of a and b? > > Bruce > > -- > You received this message because you are subscribed to the Google Groups > "Everything List" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to everything-list+unsubscr...@googlegroups.com. > To view this discussion visit > https://groups.google.com/d/msgid/everything-list/CAFxXSLSYsR4YTRH2qaGPZcBNKQ58LkUfkyY5yaNS4HuEKseLLg%40mail.gmail.com > <https://groups.google.com/d/msgid/everything-list/CAFxXSLSYsR4YTRH2qaGPZcBNKQ58LkUfkyY5yaNS4HuEKseLLg%40mail.gmail.com?utm_medium=email&utm_source=footer> > . > -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to everything-list+unsubscr...@googlegroups.com. To view this discussion visit https://groups.google.com/d/msgid/everything-list/CAMW2kAr4A6Lj%3DVxLcsDR-1_XD-5kHcjkpi526GY29UFZeDsnGw%40mail.gmail.com.
