>>Why is it a workaround? Doesn't the XPath return the XMLNode?
>>I haven't used this XPath-extension, but maybe I should check i out.

Morten, I'm not sure it returns the actual node - it might convert it to
another object instead because I too cannot get your suggestions to
work.  Could you send an xfactorstudio Xpath Actionscript example of
what you mean?  If you haven't used those classes before, then its
interesting that you are giving advice about a product you don't seem to
know the details of.  I like Mike cannot get your suggestions to work,
which if I am interpreting correctly, would mean:

myString =
XPath.selectNodes(my_xml,"rootNode/myChildNodeNode/myChildNode/").nodeVa
lue;

That returns undefined when I try it.  Or are you suggesting something
else?



Jason Merrill   |   E-Learning Solutions   |  icfconsulting.com






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