try dropping the last slash in ur xpath statement On 12/7/05, Merrill, Jason <[EMAIL PROTECTED]> wrote: > > >>Why is it a workaround? Doesn't the XPath return the XMLNode? > >>I haven't used this XPath-extension, but maybe I should check i out. > > Morten, I'm not sure it returns the actual node - it might convert it to > another object instead because I too cannot get your suggestions to > work. Could you send an xfactorstudio Xpath Actionscript example of > what you mean? If you haven't used those classes before, then its > interesting that you are giving advice about a product you don't seem to > know the details of. I like Mike cannot get your suggestions to work, > which if I am interpreting correctly, would mean: > > myString = > XPath.selectNodes(my_xml,"rootNode/myChildNodeNode/myChildNode/").nodeVa > lue; > > That returns undefined when I try it. Or are you suggesting something > else? > > > > Jason Merrill | E-Learning Solutions | icfconsulting.com > > > > > > > NOTICE: > This message is for the designated recipient only and may contain > privileged or confidential information. If you have received it in error, > please notify the sender immediately and delete the original. Any other use > of this e-mail by you is prohibited. > _______________________________________________ > Flashcoders mailing list > Flashcoders@chattyfig.figleaf.com > http://chattyfig.figleaf.com/mailman/listinfo/flashcoders >
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