sorry no, u r doing a query which returns an array, try slectSingleNode, and
that will work

On 12/7/05, Johannes Nel <[EMAIL PROTECTED]> wrote:
>
> try dropping the last slash in ur xpath statement
>
> On 12/7/05, Merrill, Jason <[EMAIL PROTECTED] > wrote:
> >
> > >>Why is it a workaround? Doesn't the XPath return the XMLNode?
> > >>I haven't used this XPath-extension, but maybe I should check i out.
> >
> > Morten, I'm not sure it returns the actual node - it might convert it to
> > another object instead because I too cannot get your suggestions to
> > work.  Could you send an xfactorstudio Xpath Actionscript example of
> > what you mean?  If you haven't used those classes before, then its
> > interesting that you are giving advice about a product you don't seem to
> > know the details of.  I like Mike cannot get your suggestions to work,
> > which if I am interpreting correctly, would mean:
> >
> > myString =
> > XPath.selectNodes(my_xml,"rootNode/myChildNodeNode/myChildNode/").nodeVa
> > lue;
> >
> > That returns undefined when I try it.  Or are you suggesting something
> > else?
> >
> >
> >
> > Jason Merrill   |   E-Learning Solutions   |  icfconsulting.com
> >
> >
> >
> >
> >
> >
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>
> --
> j:pn
>



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j:pn
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