Domingo Alvarez Duarte wrote:
> I thought like you before know that the compiler actually only allocate
> one copy for any repeated constant string, and remember sizeof() isn't a
> function it's a compile time calculation, so there is no double memory
> consumption !
>
> You can test it by yourself with something like this:
>
> #include <stdio.h>
>
> const char *str1() {return "unique";}
> const char *str2() {return "unique";}
> const char *str3() {return "unique";}
>
> int main()
> {
> printf("%p = %p = %p\n", str1(), str2(), str3());
> return 0;
> }
>
> output on my machine: 00403000 = 00403000 = 00403000
It depends on the compiler.
g++ behaves as above, but for instance with Microsoft VS 7 I get:
Z:\tmp>cl /TP foo.cxx
Microsoft (R) 32-bit C/C++ Optimizing Compiler Version 13.00.9466 for 80x86
Copyright (C) Microsoft Corporation 1984-2001. All rights reserved.
foo.cxx
Microsoft (R) Incremental Linker Version 7.00.9955
Copyright (C) Microsoft Corporation. All rights reserved.
/out:foo.exe
foo.obj
Z:\tmp>.\foo.exe
00408040 = 00408048 = 00408050
^^ ^^ ^^
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