Indeed, this also works. The only difference seems to be the additional parentheses:
(3) -> unparse(sum(1/k, k=1..n)::INFORM) (3) "sum(1/%H,equation(%H,(1..n)))" Although inconvenient (are they necessary?), I think I can handle them. Thanks for everything, Martin -- You received this message because you are subscribed to the Google Groups "FriCAS - computer algebra system" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at https://groups.google.com/group/fricas-devel. For more options, visit https://groups.google.com/d/optout.
