Derek Martin wrote:
>
> Ferenc Tamas Gyurcsan wrote:
> >
> > >206.84.220.64/255.255.255.224.
Oops, I meant to also confirm that this is correct. What is needed is a
network with 30 hosts,
which is a .224 subnet mask as shown in my stupid little table below.
In this case, the network address is 206.84.220.64 and the broadcast
address is 206.84.220.95 for the subnet you need. Those two addresses
are not hosts, and should not be assigned to hosts. Doing so may work on
some ancient (or broken) implementations of IPv4, but it's definitely a
BAD thing. All the addresses in between are valid hosts though.
>
> 255.255.255.0 00000000 254 hosts, plus network and broadcast
> .128 10000000 126 hosts, " " " "
> .192 11000000 62 hosts, " " " "
> .224 11100000 30 hosts, " " " "
> .240 11110000 14 hosts, " " " "
> .248 11111000 6 hosts, " " " "
> .252 11111100 2 hosts, " " " "
>
--
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Derek D. Martin | Senior UNIX Systems/Network Administrator
Arris Interactive | A Nortel Company
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