Take a look at http://stackoverflow.com/q/8702511/759916.

On Mon, Jan 2, 2012 at 10:35 AM, Ernest Galbrun <
[email protected]> wrote:

> It is more liquely a  wchar_t  (wide character) which is the default
> value for a litteral char. It is 32 bits large with gcc (it is
> compiler-dependent).
> --
> *Ernest Galbrun*
>
>
>
> On Mon, Jan 2, 2012 at 10:26, Carlos Guia <[email protected]>wrote:
>
>> I guess the compiler treats 'a' as an integral constant and ends up using
>> int to represent it.
>>
>> Carlos Guía
>>
>>
>>
>> On Mon, Jan 2, 2012 at 2:51 AM, Shoubhik <[email protected]> wrote:
>>
>>>    #include<stdio.h>
>>>
>>>    int main()
>>>    {
>>>
>>>            char ch;
>>>            fflush(stdin);
>>>            ch=getchar();
>>>            printf("ch= %d a=%d char=%d",
>>> sizeof(ch),sizeof('a'),sizeof(char));
>>>
>>>
>>>    }
>>>
>>> I type in 'a' (without quotes) as input , and the output I got in my
>>> ***gcc version 4.5.1*** is :
>>>
>>> ch= 1 a=4 char=1
>>>
>>> My question is :
>>>
>>> If sizeof(c) is 1 , then how can sizeof('a') be 4 ?
>>>
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