bingo At 2012-01-02 17:27:35,"Carlos Guia" <[email protected]> wrote: I guess the compiler treats 'a' as an integral constant and ends up using int to represent it.
Carlos Guía On Mon, Jan 2, 2012 at 2:51 AM, Shoubhik <[email protected]> wrote: #include<stdio.h> int main() { char ch; fflush(stdin); ch=getchar(); printf("ch= %d a=%d char=%d", sizeof(ch),sizeof('a'),sizeof(char)); } I type in 'a' (without quotes) as input , and the output I got in my ***gcc version 4.5.1*** is : ch= 1 a=4 char=1 My question is : If sizeof(c) is 1 , then how can sizeof('a') be 4 ? -- You received this message because you are subscribed to the Google Groups "Google Code Jam" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/google-code?hl=en. -- You received this message because you are subscribed to the Google Groups "Google Code Jam" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/google-code?hl=en. -- You received this message because you are subscribed to the Google Groups "Google Code Jam" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/google-code?hl=en.
