hi..take a look at this now  http://codepad.org/jHR8O5FT

On Mon, Jan 2, 2012 at 9:04 PM, Oussama Bounaim <[email protected]> wrote:

> Take a look at http://stackoverflow.com/q/8702511/759916.
>
>
> On Mon, Jan 2, 2012 at 10:35 AM, Ernest Galbrun <
> [email protected]> wrote:
>
>> It is more liquely a  wchar_t  (wide character) which is the default
>> value for a litteral char. It is 32 bits large with gcc (it is
>> compiler-dependent).
>> --
>> *Ernest Galbrun*
>>
>>
>>
>> On Mon, Jan 2, 2012 at 10:26, Carlos Guia <[email protected]>wrote:
>>
>>> I guess the compiler treats 'a' as an integral constant and ends up
>>> using int to represent it.
>>>
>>> Carlos Guía
>>>
>>>
>>>
>>> On Mon, Jan 2, 2012 at 2:51 AM, Shoubhik <[email protected]> wrote:
>>>
>>>>    #include<stdio.h>
>>>>
>>>>    int main()
>>>>    {
>>>>
>>>>            char ch;
>>>>            fflush(stdin);
>>>>            ch=getchar();
>>>>            printf("ch= %d a=%d char=%d",
>>>> sizeof(ch),sizeof('a'),sizeof(char));
>>>>
>>>>
>>>>    }
>>>>
>>>> I type in 'a' (without quotes) as input , and the output I got in my
>>>> ***gcc version 4.5.1*** is :
>>>>
>>>> ch= 1 a=4 char=1
>>>>
>>>> My question is :
>>>>
>>>> If sizeof(c) is 1 , then how can sizeof('a') be 4 ?
>>>>
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>>>>
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>
>
>
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