ok..i got it..

On Mon, Jan 2, 2012 at 9:33 PM, Oussama Bounaim <[email protected]> wrote:

> Chose C as language not c++
>
>
> On Mon, Jan 2, 2012 at 4:54 PM, mandeep <[email protected]> wrote:
>
>> hi..take a look at this now  http://codepad.org/jHR8O5FT
>>
>>
>> On Mon, Jan 2, 2012 at 9:04 PM, Oussama Bounaim <[email protected]>wrote:
>>
>>> Take a look at http://stackoverflow.com/q/8702511/759916.
>>>
>>>
>>> On Mon, Jan 2, 2012 at 10:35 AM, Ernest Galbrun <
>>> [email protected]> wrote:
>>>
>>>> It is more liquely a  wchar_t  (wide character) which is the default
>>>> value for a litteral char. It is 32 bits large with gcc (it is
>>>> compiler-dependent).
>>>> --
>>>> *Ernest Galbrun*
>>>>
>>>>
>>>>
>>>> On Mon, Jan 2, 2012 at 10:26, Carlos Guia 
>>>> <[email protected]>wrote:
>>>>
>>>>> I guess the compiler treats 'a' as an integral constant and ends up
>>>>> using int to represent it.
>>>>>
>>>>> Carlos Guía
>>>>>
>>>>>
>>>>>
>>>>> On Mon, Jan 2, 2012 at 2:51 AM, Shoubhik <[email protected]> wrote:
>>>>>
>>>>>>    #include<stdio.h>
>>>>>>
>>>>>>    int main()
>>>>>>    {
>>>>>>
>>>>>>            char ch;
>>>>>>            fflush(stdin);
>>>>>>            ch=getchar();
>>>>>>            printf("ch= %d a=%d char=%d",
>>>>>> sizeof(ch),sizeof('a'),sizeof(char));
>>>>>>
>>>>>>
>>>>>>    }
>>>>>>
>>>>>> I type in 'a' (without quotes) as input , and the output I got in my
>>>>>> ***gcc version 4.5.1*** is :
>>>>>>
>>>>>> ch= 1 a=4 char=1
>>>>>>
>>>>>> My question is :
>>>>>>
>>>>>> If sizeof(c) is 1 , then how can sizeof('a') be 4 ?
>>>>>>
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>>>>>>
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>>>
>>>
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>>> Find me on Twitter @obounaim <https://www.twitter.com/obounaim>.
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>
>
>
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