I wrote: > (.) :: ((a -> b) -> (c -> a)) -> (c -> b) > flip (.) :: ((a -> b) -> (b -> c)) -> (a -> c) Hm, let me try that again: (.) :: (a -> b) -> (c -> a) -> (c -> b) flip (.) :: (a -> b) -> (b -> c) -> (a -> c) Cheers, Ronny Wichers Schreur
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