Yes John, however, what I need is the number of days between "today" and the expiration date, adjusted for any leap days that might fall within the interval. I thought I'd try a method that multiplies the raw* number of days by 365.2425/365 (a "summation" of the non-linear formula you describe below) in order to more easily get to within a day or so of the target date.
*raw number of days = target day number minus today's day number, where day numbers are determined using simple 365-day years, relative to year zero. I'm going to plug the calculations into a spreadsheet this morning and we'll see how accurate it is. At 11:22 PM 9/12/2005, John Gilmore wrote: >There is no need to use a simplified or 'linear' leap-year correction >calculation. For any algebraic Gregorian year value y the exact signed number >of leap-year correction days in preceding years is easily calculated by the >method of inclusions and exclusions. It is just > >C(y) = 365(y - 1) > + (y - 1)//4 > - (y - 1)//100 > + (y - 1)//400 > >in which '//' denotes remainder-discarding binary-integer division. > > ================================================== Art Celestini Celestini Development Services Phone: 201-670-1674 Wyckoff, NJ ============= http://celestini.com ============= Mail sent to the "From" address used in this post will be rejected by our server. Please send off- list email to: ibmmain<at-sign>celestini<dot>com. ================================================== ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to [EMAIL PROTECTED] with the message: GET IBM-MAIN INFO Search the archives at http://bama.ua.edu/archives/ibm-main.html
