Thanks for all the suggestions. I guess I didn't make myself clear enough when I asked the question. I am NOT looking to show anything normalized, quite the opposite. What I do want to show is absolute cpu seconds used, with a horizontal line (bar, minibar, Unselectable Storage Segment :-) ) denoting what the maximum number of seconds achievable would be on the 'smallest' box. I am also NOT talking about an LPAR view (making WLM service levels irrelevant), but rather a view of the complete box, ie. for all lpars on that box using the general CPs.
>Check out SMF70MPC/MTC/MCR/MTC/MPC >The "current" set provides the (physical) number of CPs as part of the model >identifier, as well as the MSU rating. We're currently running on a z9, so I cannot yet use these fields. If I understand correctly, then an 'MSU rating' is a number like 339, specifying a capacity of 339MSU. What's the relation of an MSU rating to anything? Found a website where Al Sherkow did the same calculation that I just did: Multiply the SRM constant (as published by IBM- 20592,0206 SU/s) by 3600s. This gets me 74.131.274,16 SU/h or 74MSU per hour. Al calls that 'hardware MSU' (as opposed to 'software MSU', which appears to be the 'MSU rating'. That doesn't help me with my horizontal line, as I have no clue how to relate the 339 MSUs (supposedly available in one hour) to the 74MSU maximum that I computed. Where is my thinking going wrong? Best regards, Barbara ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to lists...@bama.ua.edu with the message: GET IBM-MAIN INFO Search the archives at http://bama.ua.edu/archives/ibm-main.html
