On Jan 26, 2008, at 7:26 PM, Paul Gilmartin wrote:
On Sat, 26 Jan 2008 17:29:58 -0600, Ed Gould wrote:
Indeed. Is service likewise available over Internet? Requirements?
Format? Conventions? Citation?
"z/VM base"? Does this mean a new customer with no previously
running
z/VM system can order z/VM delivery over Internet for
installation on
that pristine system?
Any idea on how they would do this on a bare metal box? (or for that
matter DASD fresh from the factory?)
I hadn't said bare metal. I envisioned a shop running only z/OS
and/or Linux for z/Series (TPF?) with a spare LPAR on which they
want to install z/VM, even as I downloaded Linux from Debian and
intalled it on my iBook with no local Linux system for support.
Of course, the prospective customer needs Internet access, which
doesn't come with bare metal. Download a DVD image to a desktop
system, burn it, and install from HMC?
I did find the reference the OP omitted (it's not on his "Links"
page last updated in 2006):
http://www.vm.ibm.com/buy/edelivery/
... which offers little information until one signs a PO:
4. When you see the catalog list, select DDR and then select
Internet
...
The internet download can be performed using the instructions
that are in the post-order email or by clicking on the Internet
Download link on the order status page.
... but grouping with DDR suggests it's DDR unloaded format. Can
VM DDR be restored to DASD using non-VM systems? Perhaps they
supply a z/OS, Linux, or standalone restore program. Hmmm. DDR
is a totally unrelated initialism in z/OS.
I'm intrigued by the question of how a new z/Series installation
gets started. Of course, this is relevant only if there are new
z/Series installations, not dissuaded by their first glimpse of
JCL.
-- gil
Gil:
Thanks for the clarification.
I think I have heard of people on here doing a *LARGE* receive on
here but to order an *ENTIRE* OS boggles my mind. I have not done a
VM installation in 20++ years so I don't have any idea how big it
would be. The last MVS order I saw was approximately 18 3480 tapes. I
wouldn't think (but I am obviously wrong) that a checksum could be
that large to hold the amount of data. I am somewhat curious as to
how many tapes a Z/vm order is, anyone?
Ed
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