Hi Tien,
Are you referring that "Vi-1" is "V sub i minus1" and "Vi+1" is "V sub i
plus 1"?
| ( Vi-1 - Vi ) - ( Vi - Vi+1 ) |
----
Chris Kim
Iowa State University
>From: Robert Pies <[EMAIL PROTECTED]>
>Reply-To: Discussion list for Java 3D API <[EMAIL PROTECTED]>
>To: [EMAIL PROTECTED]
>Subject: Re: [JAVA3D]
>Date: Tue, 6 Feb 2001 13:30:19 +0100
>
>Hi Tien,
>
>I can't make sense out of your expression for at least 2 reasons:
>
>a) if Vi is a vector (xi,yi), the term 'Vi-1' doesn't make sense
>b) 'Vi-Vi' would be (0,0), so all the Vi's in your expression cancel
> out...
>
>Maybe the '-' in your expression is really a '*' denoting the
>(inner) vector-product?
>
>If you tell the mailinglist what you're trying to do, maybe some-
>one can make sense of it and help you.
>
>cheers,
>
>Robert.
>
>
>
> > Tien Tran Thuong wrote:
> >
> > Hello,
> >
> > Could anyone show me please how to calculate the expression below :
> >
> > | ( Vi-1 - Vi ) - ( Vi - Vi+1 ) |
> >
> > Where Vi = (xi,yi) is coordinate of the i-th vertex.
> >
> > Thank you in advance
>
>--
>
>---------------------------------------------------
>Robert Pies
>Ludwigstr. 58
>04315 Leipzig
>Germany
>+49-341-6888217 (phone&fax)
>[EMAIL PROTECTED]
>
>
>--
>
>---------------------------------------------------
>Robert Pies
>Ludwigstr. 58
>04315 Leipzig
>Germany
>+49-341-6888217 (phone&fax)
>[EMAIL PROTECTED]
>
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