thank you for you reply
there are three point: i, j and k.
Vi = (Xi, Yi), Vj = (Xj, Yj) and Vk = (Xk, Yk) are the coordinates of i,j,k
I'd like to know how to calculate:
| ( Vi - Vj ) - ( Vj - Vk ) |
it's knew that : | Vi - Vj | = Math.sqrt( (Xi-Xj)*(Xi-Xj) -
(Yi-Yj)*(Yi-Yj) )
thank you
> Hi Tien,
>
> Are you referring that "Vi-1" is "V sub i minus1" and "Vi+1" is "V sub i
> plus 1"?
>
> | ( Vi-1 - Vi ) - ( Vi - Vi+1 ) |
>
> ----
> Chris Kim
> Iowa State University
>
> >From: Robert Pies <[EMAIL PROTECTED]>
> >Reply-To: Discussion list for Java 3D API <[EMAIL PROTECTED]>
> >To: [EMAIL PROTECTED]
> >Subject: Re: [JAVA3D]
> >Date: Tue, 6 Feb 2001 13:30:19 +0100
> >
> >Hi Tien,
> >
> >I can't make sense out of your expression for at least 2 reasons:
> >
> >a) if Vi is a vector (xi,yi), the term 'Vi-1' doesn't make sense
> >b) 'Vi-Vi' would be (0,0), so all the Vi's in your expression cancel
> > out...
> >
> >Maybe the '-' in your expression is really a '*' denoting the
> >(inner) vector-product?
> >
> >If you tell the mailinglist what you're trying to do, maybe some-
> >one can make sense of it and help you.
> >
> >cheers,
> >
> >Robert.
> >
> >
> >
> > > Tien Tran Thuong wrote:
> > >
> > > Hello,
> > >
> > > Could anyone show me please how to calculate the expression below :
> > >
> > > | ( Vi-1 - Vi ) - ( Vi - Vi+1 ) |
> > >
> > > Where Vi = (xi,yi) is coordinate of the i-th vertex.
> > >
> > > Thank you in advance
> >
> >--
> >
> >---------------------------------------------------
> >Robert Pies
> >Ludwigstr. 58
> >04315 Leipzig
> >Germany
> >+49-341-6888217 (phone&fax)
> >[EMAIL PROTECTED]
> >
> >
> >--
> >
> >---------------------------------------------------
> >Robert Pies
> >Ludwigstr. 58
> >04315 Leipzig
> >Germany
> >+49-341-6888217 (phone&fax)
> >[EMAIL PROTECTED]
> >
>
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