On Mon, Jun 9, 2008 at 3:16 PM, Robert Donovan <[EMAIL PROTECTED]> wrote:
> On Mon, Jun 9, 2008 at 3:11 PM, Robert Donovan <[EMAIL PROTECTED]> wrote:
>> On Mon, Jun 9, 2008 at 2:55 PM, Todd Walton <[EMAIL PROTECTED]> wrote:
>>> On Fri, Jun 6, 2008 at 11:23 AM, Chris Louden <[EMAIL PROTECTED]> wrote:
>>>> On Fri, Jun 6, 2008 at 9:07 AM, Todd Walton <[EMAIL PROTECTED]> wrote:
>>>>> 167.190.1.24 (address) and 255.255.255.248 (mask)
>>>>>
>>>>> which yields an IP range of... ?
>>>>
>>>> 167.190.1.25 - 167.190.1.30
>>>>
>>>>>
>>>>> Sometimes the mask is like 255.255.240.0 or 255.255.255.192.  Aagh!
>>>>
>>>> 167.190.0.1 - 167.190.15.254
>>>> or
>>>> 167.190.1.1 - 167.190.1.62
>>>
>>> With a network address of 167.190.1.24 and a mask of 255.255.255.192,
>>> wouldn't the range be:
>>>
>>> 167.190.1.25 to 167.190.1.254?
>>>
>>> -todd
>
> Sorry, again, several typos, and the fact that I got into a hurry and forgot 
> to post
the full range of subnets, made that last post really annoying too.

For the third, and hopefully final, time:
Your theoretical subnets would be 192.168.1.0, 192.168.1.64,
192.168.1.128, and 192.168.1.192.
By strict classful subnetting, you can't use 192.168.1.0 because it is
defining the subnet address.
You can use 192.168.1.64 and 192.168.1.128.
You can't use 192.168.1.192, because is is defining the subnet mask.
Your first subnet address would be 192.168.1.64, with a range of
192.168.1.65 to 192.168.1.127,
and your second available subnet would be 192.168.1.128, with a range
of 192.168.1.129 to 192.168.1.191.

Read this http://www.tradecraftsolutions.com/TCSMain/Sub-supernets.odt
for further details.

Robert Donovan


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