Ok - I just checked in these changes. It will use the old algorithm unless
you pass skip_renumber...
Derek
On Fri, May 25, 2012 at 12:57 PM, Roy Stogner <royst...@ices.utexas.edu>wrote:
>
> Sorry, was gone for a bit.
>
> Sticking with the old algorithm in the non-skip_renumbering case is
> probably the best way to go if you're in a hurry. However, I wouldn't
> worry about restart files - don't we always libHilbert-renumber the
> solution data anyway?
> ---
> Roy
>
>
> On Fri, 25 May 2012, Derek Gaston wrote:
>
> Any input here? I'm probably going to do what I said... run the original
>> algorithm unless they say "skip_renumbering"....
>> I need to get this fixed (have some users waiting on it)....
>>
>> Derek
>>
>> On Fri, May 25, 2012 at 7:52 AM, Derek Gaston <fried...@gmail.com> wrote:
>> Right - good idea!
>> However, I just thought of something else. With my new code the original
>> mesh won't ever be renumbered. I'm sure there are quite a few
>> restart files and other things that are depending on that old
>> renumbering. Should I maybe restore the old algorithm... and only do the
>> new
>> algorithm if they've asked to "skip_renumbering" ?
>>
>> Derek
>>
>> On Thu, May 24, 2012 at 12:36 PM, Roy Stogner <royst...@ices.utexas.edu>
>> wrote:
>>
>> On Thu, 24 May 2012, Derek Gaston wrote:
>>
>> HOWEVER: This is now a 2nLog(n) algorithm... where n is the
>> number
>> of nodes in your mesh.
>>
>>
>> Replace std::set with LIBMESH_BEST_UNORDERED_SET and (as long as
>> configure found a gnu or tr1 or c++11 hash table container) we ought
>> to be back to O(n). Since you're not actually trying to iterate
>> through connected_nodes in order, just testing for set inclusion
>> later, there's no need to preserve ordering. The hash tables probably
>> take up more memory, but I don't think the difference will be
>> too bad - might want to benchmark (both RAM and CPU usage) to be sure.
>> ---
>> Roy
>>
>>
>>
>>
>>
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