On Thu, Jul 16, 2026 at 02:38:58PM +0000, Pu Hu wrote:
> On 7/16/2026 9:24 PM, Will Deacon wrote:
> > On Fri, Jul 10, 2026 at 06:32:55AM +0000, Pu Hu wrote:
> >> From: Pu Hu <[email protected]>
> >>
> >> A kprobe can be hit while another kprobe is in KPROBE_HIT_SS state. This
> >> can happen when tracing or perf code runs from the debug exception path
> >> while the first kprobe is preparing or executing its out-of-line
> >> single-step instruction.
> > 
> > I don't understand this part. The single-step runs with debug exceptions
> > disabled (kprobes_save_local_irqflag() sets PSTATE.D) so how do we end
> > up taking one?
>
> You are right that the single-step runs with debug exceptions disabled.
> However, the case I was referring to is not a hardware breakpoint or a
> software-step exception, but another Breakpoint Instruction exception
> generated by executing a BRK instruction. A BRK instruction exception is 
> not masked by PSTATE.D, so it can still be taken while handling a kprobe.
> 
> As far as I understand the architecture, there are two different cases here:
> 
>    - Breakpoint Instruction exceptions, generated by executing a BRK
>      instruction.
>    - Breakpoint exceptions, generated by the debug logic, for example by
>      programmed breakpoint registers.
> 
> PSTATE.D masks debug exceptions such as hardware breakpoints, 
> watchpoints and software-step exceptions, but it does not mask 
> Breakpoint Instruction exceptions generated by BRK. This also seems 
> consistent with the pseudocode for BRK, 
> Arch64.SoftwareBreakpoint(imm16), which does not appear to check 
> PSTATE.D before taking the exception.
> 
> Therefore, even if kprobes_save_local_irqflag() sets PSTATE.D while 
> handling the first kprobe, if the code executed from that path reaches 
> another instruction patched with BRK, it can still take a Breakpoint 
> Instruction exception. In other words, the nested case I mentioned is 
> another kprobe BRK being hit, not a hardware debug exception or a 
> software-step exception.

Yes, that's correct, but if we're doing the out-of-line step, how do we
end up executing a BRK? Or are you saying that it's the kprobes
BRK64_OPCODE_KPROBES_SS instruction that we use to implement the
single-step that is the problem? If so, how does taking that exception
result in us executing tracing or perf code?

Sorry for all the questions, I just haven't understood what's going on
here from the commit message.

Will

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