On 7/16/2026 11:20 PM, Will Deacon wrote:
> On Thu, Jul 16, 2026 at 02:38:58PM +0000, Pu Hu wrote:
>> On 7/16/2026 9:24 PM, Will Deacon wrote:
>>> On Fri, Jul 10, 2026 at 06:32:55AM +0000, Pu Hu wrote:
>>>> From: Pu Hu <[email protected]>
>>>>
>>>> A kprobe can be hit while another kprobe is in KPROBE_HIT_SS state. This
>>>> can happen when tracing or perf code runs from the debug exception path
>>>> while the first kprobe is preparing or executing its out-of-line
>>>> single-step instruction.
>>>
>>> I don't understand this part. The single-step runs with debug exceptions
>>> disabled (kprobes_save_local_irqflag() sets PSTATE.D) so how do we end
>>> up taking one?
>>
>> You are right that the single-step runs with debug exceptions disabled.
>> However, the case I was referring to is not a hardware breakpoint or a
>> software-step exception, but another Breakpoint Instruction exception
>> generated by executing a BRK instruction. A BRK instruction exception is
>> not masked by PSTATE.D, so it can still be taken while handling a kprobe.
>>
>> As far as I understand the architecture, there are two different cases here:
>>
>>     - Breakpoint Instruction exceptions, generated by executing a BRK
>>       instruction.
>>     - Breakpoint exceptions, generated by the debug logic, for example by
>>       programmed breakpoint registers.
>>
>> PSTATE.D masks debug exceptions such as hardware breakpoints,
>> watchpoints and software-step exceptions, but it does not mask
>> Breakpoint Instruction exceptions generated by BRK. This also seems
>> consistent with the pseudocode for BRK,
>> Arch64.SoftwareBreakpoint(imm16), which does not appear to check
>> PSTATE.D before taking the exception.
>>
>> Therefore, even if kprobes_save_local_irqflag() sets PSTATE.D while
>> handling the first kprobe, if the code executed from that path reaches
>> another instruction patched with BRK, it can still take a Breakpoint
>> Instruction exception. In other words, the nested case I mentioned is
>> another kprobe BRK being hit, not a hardware debug exception or a
>> software-step exception.
> 
> Yes, that's correct, but if we're doing the out-of-line step, how do we
> end up executing a BRK? Or are you saying that it's the kprobes
> BRK64_OPCODE_KPROBES_SS instruction that we use to implement the
> single-step that is the problem? If so, how does taking that exception
> result in us executing tracing or perf code?
> 
> Sorry for all the questions, I just haven't understood what's going on
> here from the commit message.

The key is that, when you use 'perf --call-graph dwarf' to sample 
certain events, kernel perf code will sample a piece of user stack each 
time those events are hit, and copy_to/from_user() triggers page faults. 
Say you are profiling preempt_enable events:

1st BRK -> preempt_disable() -> debug_exception() -> set SS state -> 
preempt_enable() -> triggers perf -> perf_sample() -> sample user stack 
using copy_to/from_user() -> page fault or 2nd BRK on the page fault path.

The key is perf sampling the user stack while the 1st BRK is still 
running. When a page fault is hit, a can of worms is released, including 
a possible 2nd BRK.

Hongyan

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