>echo abcdefghijklmnopqrstuvwxyz | sed 'keep first 5 chars, then append
a Z to every fourth char thereafter, and keep the leftovers too'
Had another look at this last night, if you still interested in a purely
sed solution the following works I think (on Linux Mint at least - you
will need to escape the regular expression stuff since you don't have
-r). Also doesn't care if there are already 'Z's in the line:
sed -r 'h; s/(.).*/\1/g; x; s/.(.*)/\1/g; s/(.{4})/\1Z/g; x; G;
s/\n//g;'
Terrible stuff to read however so breaking it down
h; = copy pattern space (input) to hold space
s/(.).*/\1/g; = get the first character only
x; = swap pattern and hold spaces (so now working against
original input)
s/.(.*)/\1/g; = remove the first character
s/(.{4})/\1Z/g; = every fourth character add in a Z
x; = swap pattern and hold space again (pattern now has 1st
char, hold has Z'd stuff)
G; = append hold space to pattern space
s/\n//g; = remove the newline inserted when space above
got appended.
Regards,
Bryce Stenberg.
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