Jim,
 There are different types of solar controllers.
 Some need a "bypass load" connected (like a 12 volt water heater element), 
some do not.

 If you buy a "smart" controller the "input resistance" varies with the 
stage of the charge cycle. During "bulk mode" the current is allowed to flow 
freely, during "absorption mode" the output voltage is controlled at the 
proper voltage for your battery type and (hopefully) the battery 
temperature, so the "input resistance" will increase steadily as the battery 
approaches full charge. When the charge controller decides to switch to 
"float mode" the "input resistance" changes to regulate the output voltage 
to the proper voltage for your battery type and (again, hopefully) 
temperature.

Due to the presence of blocking diodes both scenarios are wrong.
 If one panel is putting out a lower voltage than the other (maybe partially 
shaded or pointed less directly toward the sun) the higher voltage of the 
other "parallel" panel will hold the diode in reverse bias and no current 
will flow from the panel with the lower voltage.
 Unless the panels are very nearly identical, a parallel wiring system will 
produce unsatisfactory results.
 Luckily, panels of the same size from the same manufacturer and of nearly 
the same age will work just fine in a parallel wiring setup.


Eric Thompson
S/V Procrastinator
South San Francisco
[email protected]

----- Original Message ----- 
From: "Jim" <[email protected]>
To: <[email protected]>
Sent: Sunday, April 05, 2009 7:11 PM
Subject: Re: [Liveaboard] Solar charge controller


> Ben Okopnik wrote:
>> On Sun, Apr 05, 2009 at 08:09:49PM -0400, Jim wrote:
>>
>>>>
>>>>
>>> Here's my thinking and I don't know how the controllers work so I may be
>>> off base.  If you have two voltage sources in parallel and one of them
>>> is generating a higher voltage, current will flow from the higher
>>> voltage source to the lower voltage source and the load.
>>>
>>
>> Please correct me if I'm worng :) - but isn't "voltage is the same
>> everywhere in a parallel circuit, current varies" part of Ohm's Law?  I
>> may be 20-some years out of practice, but I think I recall that one
>> correctly. I suspect that you were thinking of internal resistance
>> rather than voltages.
>>
> Yes, but I was referring to two different voltage sources like a 9 volt
> battery and a 12 volt battery.  If you connect them together you will
> have a voltage of something in between, but that doesn't change the fact
> each have a voltage associated with them until you connect them.  That's
> what I was referring to as a voltage source.
>> In addition, current in a pair of paralleled generators is additive;
>> current from a larger one will not flow through a smaller one, since
>> there's no voltage differential, but will simply be added to the total.
>>
> If there is a differential when not connected, then current will either
> flow from one to the other (and the load) or from the higher potential
> to the load if the lower potential source will not allow incoming
> current.  That is true if the load is of a high enough resistance to
> permit the voltage at the connection between the two generators to
> remain above the potential of the lower potential source.
>>
>>> So I'm guessing that the input impedance (resistance) of a controller is
>>> very low such that the panels are almost short circuited and there is
>>> almost no measurable voltage at the input of the controller.  Then
>>> current from both sources would be available.
>>>
>>
>> That's not exactly how internal resistance (not impedance - that would
>> only matter in an AC circuit, and not "input resistance" - there's
>> really no such thing) works. I'm sure that it _is_ low for these
>> controllers - there'd be no reason for it to be otherwise, and the
>> controller wouldn't be able to work if it was - but the input of that
>> controller is, again, a parallel connection:
>>
>>  .______.______________.
>>  |      |              |
>>  |+     |+             |+
>> ---    ---         ----------
>>  -      -         |Controller|
>>  |-     |-         ----------
>>  |      |              |-
>>  -----------------------
>>
>> Hence, the voltage will be the same at the controller input as it is at
>> the panel output, barring a tiny drop through the wires (which are a
>> series connection, of course.)
>>
> Yes, if the controller has a low input  resistance as I mentioned, both
> sources will feed current to the controller.  I was merely thinking out
> loud about what that resistance would have to be.  I used the term
> impedance because I'm fairly certain that the circuit is not 100%
> resistive in nature and will have some reactance but I'm not completely
> certain of that.  If so then my use of the term impedance is at least
> tolerable.   ;)  I can run a simulation of various loads to demonstrate
> my contention, if you wish.
>
> It's  a moot point however since the controllers work.  I was just
> having a problem getting my arms around how and I, as I said, was
> thinking out loud to come to the conclusion the controller has a low
> input impedance.
>
> That said, can anyone tell me what the input voltage does when the load
> on the controller is removed?  Does it go up or does the controller dump
> the excess current into an internal load.
>
> Thanks,
> Jim.
>>
>>> That analysis didn't come to the conclusion I was aiming for, but that's
>>> OK.  It supports Lee's suggestion.  If there is a marginal advantage to
>>> two controllers, it's probably not worth it.
>>>
>>
>> My analysis is essentially the opposite of yours, and yet I agree with
>> your conclusion. Given the cost of a controller, and the gain to be had
>> for that cost, you'd be much better off buying more panels with that
>> money, and just enough controller capacity (plus a safety margin) to
>> handle that panel output.
>>
>>
>>
>
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