Re: [Machinekit] M66 question

[schoone...@btinternet.com]

It appears that the Q input is of type double, which means it will only wait for 28,561.6 years before moving again So set it to a high number and effectively it will never move again without an input. Or you can enter a shorter period and test the value of #5399 to see if it is -1 indicating a timeout. In that event you can abort. On 02/12/17 15:15, Sag ich Dir nich wrote: The manual says "M66 wait on an input stops further execution of the program, until the selected event (or the programmed timeout) occurs." so that means if the machine waits for an input but then the timeout occurs, the machine continues? Thats not logical to me. I would like the machine to stop if the timeout occurs.  In case you were wondering why i bother, its for an automatic toolchanger to let the machine know if the pull stud is in the correct position to prevent expensiveness, if it is not in the correct position, the machine waits until it is... or gets an timeout and stops further execution.  thanks -- website: http://www.machinekit.io blog: http://blog.machinekit.io github: https://github.com/machinekit --- You received this message because you are subscribed to the Google Groups "Machinekit" group. To unsubscribe from this group and stop receiving emails from it, send an email to machinekit+unsubscr...@googlegroups.com. Visit this group at https://groups.google.com/group/machinekit. For more options, visit https://groups.google.com/d/optout. -- website: http://www.machinekit.io blog: http://blog.machinekit.io github: https://github.com/machinekit --- You received this message because you are subscribed to the Google Groups "Machinekit" group. To unsubscribe from this group and stop receiving emails from it, send an email to machinekit+unsubscr...@googlegroups.com. Visit this group at https://groups.google.com/group/machinekit. For more options, visit https://groups.google.com/d/optout.