okay, yes i will do a video once i have completely modeled and built my 
machine :) It is still in development so could take a while

Am Samstag, 2. Dezember 2017 20:33:27 UTC+1 schrieb John Morris:
>
>
>
> On 12/02/2017 12:00 PM, [email protected] <javascript:> wrote: 
> > 
> > On 02/12/17 17:20, Sag ich Dir nich wrote: 
> >> okay thank you, i will try that. 
> >> 
> >> one more question, does the next M66 reset #5399? 
> > 
> > You will need to experiment, set a short timeout M66 and don't send a 
> > signal, to set it to -1, then set a longer one and send a signal before 
> > it times out. 
> > #5399 should contain 0 or 1 typically but never -1 
>
> Oops, fired off that last message too soon.  Mick's right:  M66 L[1-4] 
> is for digital inputs only; after execution, it will hold the value of 
> the digital input specified by the P flag, or -1 in case of timeout. 
>
> Also, the P flag can range from 0 to 63 (IIRC) if you set `loadrt motmod 
> num_dio=64` in the HAL file; the M66 manual isn't quite right on that 
> point. 
>
> I haven't been following your project, but I hope I get to see a video 
> of your tool changer in operation once you're done with it! 
>
>         John 
>
> > 
> > I don't know if #5399 is set to anything before M66 exits, I would 
> > suspect it would hold the last entered value until M66 exits for 
> > whatever reason 
> > and sets the return value accordingly. 
> > You will need to verify, but suspect #5399 is meaningless until M66 does 
> > exit. 
> > 
> >> 
> >> Am Samstag, 2. Dezember 2017 16:54:35 UTC+1 schrieb Schooner: 
> >> 
> >>     It appears that the Q input is of type double, which means it will 
> >>     *only* wait for 28,561.6 years before moving again 
> >> 
> >>     So set it to a high number and effectively it will never move 
> >>     again without an input. 
> >> 
> >>     Or you can enter a shorter period and test the value of #5399 to 
> >>     see if it is -1 indicating a timeout. 
> >>     In that event you can abort. 
> >> 
> >> 
> >>     On 02/12/17 15:15, Sag ich Dir nich wrote: 
> >>>     The manual says "M66 wait on an input stops further execution of 
> >>>     the program, until the selected event (or the programmed timeout) 
> >>>     occurs." 
> >>> 
> >>>     so that means if the machine waits for an input but then the 
> >>>     timeout occurs, the machine continues? Thats not logical to me. I 
> >>>     would like the machine to stop if the timeout occurs. 
> >>> 
> >>>     In case you were wondering why i bother, its for an automatic 
> >>>     toolchanger to let the machine know if the pull stud is in the 
> >>>     correct position to prevent expensiveness, if it is not in the 
> >>>     correct position, the machine waits until it is... or gets an 
> >>>     timeout and stops further execution. 
> >>> 
> >>>     thanks 
> >>>     -- 
> >>>     website: http://www.machinekit.io blog: http://blog.machinekit.io 
> >>>     github: https://github.com/machinekit 
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> >> 
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