On 02/12/17 17:20, Sag ich Dir nich
wrote:
okay thank you, i will try that.
one more question, does the next M66 reset #5399?
You will need to experiment, set a short timeout M66 and don't send
a signal, to set it to -1, then set a longer one and send a signal
before
it times out.
#5399 should contain 0 or 1 typically but never -1
I don't know if #5399 is set to anything before M66 exits, I would
suspect it would hold the last entered value until M66 exits for
whatever reason
and sets the return value accordingly.
You will need to verify, but suspect #5399 is meaningless until M66
does exit.
Am Samstag, 2. Dezember 2017 16:54:35 UTC+1 schrieb Schooner:
It appears that the Q
input is of type double, which means it will only
wait for 28,561.6 years before moving again
So set it to a high number and effectively it will never
move again without an input.
Or you can enter a shorter period and test the value of
#5399 to see if it is -1 indicating a timeout.
In that event you can abort.
On 02/12/17 15:15, Sag ich Dir nich wrote:
The manual says " M66
wait on an input stops further execution of the
program, until the selected event (or the programmed
timeout) occurs."
so that means if the machine waits for an input
but then the timeout occurs, the machine continues?
Thats not logical to me. I would like the machine to
stop if the timeout occurs.
In case you were wondering why i bother, its for
an automatic toolchanger to let the machine know if
the pull stud is in the correct position to prevent
expensiveness, if it is not in the correct position,
the machine waits until it is... or gets an timeout
and stops further execution.
thanks
website: http://www.machinekit.io blog: http://blog.machinekit.io github: https://github.com/machinekit
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