On Nov 9, 2006, at 11:37 AM, Cassio B. Caporal wrote:
Hey,
I have problems to print '%' in stdout... Suppose code below:
#include <stdio.h>
main() {
char foo[] = "bar=30%\n";
fprintf(stdout, bar);
}
OpenBSD returns : bar=30
Linux returns : bar=30%
How can I solve this? Thanks,
$ cat foo.c
#include <stdio.h>
main() {
char foo[] = "bar=30%%\n";
fprintf(stdout, foo);
}
$ gcc foo.c -o foo
$ ./foo
bar=30%
--
Jason Dixon
DixonGroup Consulting
http://www.dixongroup.net
