Yes, but I read lines from a file.. I wrote a function that add one
more '%' and works fine. Thanks!
Jason Dixon wrote:
> On Nov 9, 2006, at 11:37 AM, Cassio B. Caporal wrote:
>
>> Hey,
>>
>> I have problems to print '%' in stdout... Suppose code below:
>>
>> #include <stdio.h>
>>
>> main() {
>> char foo[] = "bar=30%\n";
>> fprintf(stdout, bar);
>> }
>>
>> OpenBSD returns : bar=30
>> Linux returns : bar=30%
>>
>> How can I solve this? Thanks,
>
> $ cat foo.c
> #include <stdio.h>
>
> main() {
> char foo[] = "bar=30%%\n";
> fprintf(stdout, foo);
> }
> $ gcc foo.c -o foo
> $ ./foo
> bar=30%
>
>
> --
> Jason Dixon
> DixonGroup Consulting
> http://www.dixongroup.net
