Re: % stdout?

[Matthew Closson]

On Thu, 9 Nov 2006, Cassio B. Caporal wrote:

        Hey,

        I have problems to print '%' in stdout... Suppose code below:

                #include <stdio.h>

                main() {
                         char foo[] = "bar=30%\n";
                         fprintf(stdout, bar);
                }

        OpenBSD returns : bar=30
        Linux returns   : bar=30%

        How can I solve this? Thanks,

Use the format specifier with fprintf:

#include <stdio.h>

int main()
{
  char foo[] = "bar=30%\n";
  fprintf(stdout, "%s", foo);
}

cc test.c
./a.out
bar=30%


                -Matt-