Re: % stdout?

[John Wright]

On Nov 9, 2006, at 11:37 AM, Cassio B. Caporal wrote:
>       Hey,
>
>       I have problems to print '%' in stdout... Suppose code below:
>
>               #include <stdio.h>
>
>               main() {
>                        char foo[] = "bar=30%\n";
>                        fprintf(stdout, bar);
>               }
>
>       OpenBSD returns : bar=30
>       Linux returns   : bar=30%
>
>       How can I solve this? Thanks,

fprintf(stdout, "%s", foo);