Each bit traverses only one peering session, however, at the "top of its
trajectory" to use a physical metaphor. The uphill and downhill sides are all
transit.
-Bill
> On Feb 17, 2016, at 14:06, Owen DeLong <[email protected]> wrote:
>
>
>> The premise above therefore devolves to: Since most of the traffic is to
>> those networks, then most of the bits flow over contracted peerings.
>>
>> Perhaps “most” can be argued, but obviously a significant portion of all
>> peering bits flow over contracted sessions. Hopefully we can all agree on
>> that.
>
> There’s greater complexity here, however…
>
> Many of the bits that flow flow over several networks between their source
> and destination. Likely the vast majority of bits traverse at least 3
> autonomous systems in the process.
>
> So when you want to count traffic that went over a non-contract peering
> session vs. traffic that went over a contract peering session, how do you
> count traffic that traverses some of each?
>
> Owen
>
