Thank you guys. I will give those approaches a whirl.

cheers!

On Thu, May 24, 2012 at 12:17 AM, Torax Unga <[email protected]> wrote:

> Each swatch should be a solid color and a different specific position in
> the RGB curves graph. I don't have Nuke in front of me, but you should be
> able to sample each swatch on the source and destination images and create
> several keys in the curve graph.
>
>   ------------------------------
> *From:* Jason Huang <[email protected]>
> *To:* Torax Unga <[email protected]>; Nuke user discussion <
> [email protected]>
> *Sent:* Wednesday, 23 May 2012, 16:05
> *Subject:* Re: [Nuke-users] match color charts between HDR and plate for
> every color swa
>
> I haven't tried the ColorLookup node for this. But say I matched the first
> swatch, how can I match the next swatch with the ColorLookup without
> affecting the first swatch that I just matched (and moving forward to match
> all remaining swatches)? This is the part puzzling me....
>
> On Wed, May 23, 2012 at 2:13 PM, Torax Unga <[email protected]> wrote:
>
> You can try using a ColorLookup and sample/match every swatch.
> There is also this:
> http://www.lightillusion.com/matchlight.html
>
>   ------------------------------
> *From:* jasonhuang1115 <[email protected]>
> *To:* [email protected]
> *Sent:* Wednesday, 23 May 2012, 11:24
> *Subject:* [Nuke-users] match color charts between HDR and plate for
> every color swa
>
>  Hi,
>
> I am not sure if this is commonly handled in Nuke by compers or look-dev
> artists. Say in the case I have the Macbeth color chart shot as part of the
> HDR environment map and also a still frame of the chart shot by the plate
> camera (camera setting kept the same). If I want to match the color of the
> HDR environment map to the plate based the color charts, how should I match
> very closely every single swatch of the color chart presented in the two
> images?
>
> I have tried to use the grade node for the black point and the white
> point, but it doesn’t give me close match for all the color swatches. I
> guess there is a color transformation between the two?
>
> Thanks.
>
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