On Tue, 29 Nov 2005 14:31:56 -0500
Timothy Miller <[EMAIL PROTECTED]> wrote:
> What happens when the logic tries to compare a 0 or a 1
> to a metastable bit? Is that horrible? Or does it actually come up
> with an answer?
That higly depends on the underlying circuit. There
are basicaly two possibilities: The comparator treats
the metastable value as a random 1 or 0 and thus comes
up with an answer, but that might be wrong. The second
is that the comparator input flips between 0 and 1 and
thus does the comparator output. This might also result
in an metastable state at the next register (though very
unlikely).
Unfortunately i do not know what kind of circuitry
Xilinx/Lattice have at their inputs, thus cannot say
which one of the above posibilities it is.
Attila Kinali
--
wer soviel schoggi isst, kann sowieso nicht dumm sein ;-)
-- Sandra
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