On 6/16/06, Tom Cook <[EMAIL PROTECTED]> wrote:
To shift this into C:
char whatsit( char a, char b, bool d )
{
if( d ) return a & b;
else return (a + b) & 0x0F;
}
The carry bit from the addition is being lost (hence the & 0x0F at the end
of the addition). Also char is 4 bits wider than the types of the Verilog,
but it's the nearest C equivalent.
Do I win?
In this game, EVERYBODY wins. :)
(Wasn't that just the cheeziest thing to say? :)
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