Its ok, I've made some test and I understand how it works now... thanks for
the help.
I've another question, a similar one but I think I can ask it here :
If my node is a PAT i do
quat = pat->getAttitude();
if my node is a MatrixTransform i do
quat = mt->getMatrix().getRotate();
But in the second case, it looks doing nothing... Where is the difference ?
Thanks.
Regards,
Vincent
2008/3/27, Alberto Luaces <[EMAIL PROTECTED]>:
>
> Sorry if I don't understand you again, but my program is giving you the
> absolute position of the node (the fourth column of the matrix,
> (10,20,-5))
> and its world orientation ( the first 3x3 block, equal to identity since
> the
> two transforms were translation ones).
>
> Try changing m1 and m2 to see the changes in the global position and
> orientation.
>
> El Jueves 27 Marzo 2008ES 17:31:51 Vincent Bourdier escribió:
>
> > In your example you are using getWorldMatrices.
> > I know this function, thanks... I and Robert were talking about it.
> > But what I simply need is :
> >
> > with a node, I need its position (absolute/world coordinates), and its
> > orientation (in the world system coordinates).
> > How can I do it ?
> >
> > (Sorry, I'm not very understandable...)
> >
> > Thanks,
> >
> > Regard.
> > Vincent.
> >
> > 2008/3/27, Alberto Luaces <[EMAIL PROTECTED]>:
> > > Sorry, I don't get what you exactly are looking for. Would this
> example
> > > help?
> > > It calculates the position of a node in world coordinates:
> > >
> > > #include <osg/Node>
> > > #include <osg/Group>
> > > #include <osg/Matrix>
> > > #include <osg/MatrixTransform>
> > >
> > > #include <iostream>
> > >
> > > int main()
> > > {
> > > osg::Group *root;
> > > osg::Node *n;
> > > osg::MatrixTransform *m1, *m2;
> > >
> > > root = new osg::Group;
> > > n = new osg::Node;
> > > m1 = new osg::MatrixTransform(
> osg::Matrix::translate(osg::Vec3
> > > (0.0,10.0,0.0)));
> > > m2 = new osg::MatrixTransform(
> osg::Matrix::translate(osg::Vec3
> > > (10.0,10.0,-5.0)));
> > >
> > > // root->m1->m2->n
> > >
> > > root->addChild(m1);
> > > m1->addChild(m2);
> > > m2->addChild(n);
> > >
> > > osg::MatrixList ml = n->getWorldMatrices();
> > >
> > > for(int i=0; i<4; i++)
> > > {
> > > for(int j=0; j<4; j++)
> > > {
> > > std::cout << ml[0](j,i) << "\t";
> > > }
> > > std::cout << "\n";
> > > }
> > >
> > > return 0;
> > > }
> > >
> > > El Jueves 27 Marzo 2008ES 16:24:47 Vincent Bourdier escribió:
> > > > Hi Alberto
> > > >
> > > > Thanks for help, I understand the instance problem... If all is good
> in
> > >
> > > my
> > >
> > > > situation I would not have many instances of the same node... so I
> > > > think
> > >
> > > it
> > >
> > > > will be more simple...
> > > >
> > > > Because my problem is more recent, I ask a second question : To get
> > > > this node's position (absolute ), if I understand well I must use
> > > > something
> > >
> > > like
> > >
> > >
> > >
> http://www.openscenegraph.org/projects/osg/wiki/Support/Tutorials/CameraC
> > >on
> > >
> > > >trolFindingWorldCoordinates
> > > >
> > > > There is no other way ?
> > > >
> > > > Thanks,
> > > >
> > > > Regards.
> > > > vincent.
> > > >
> > > > 2008/3/27, Alberto Luaces <[EMAIL PROTECTED]>:
> > > > > El Jueves 27 Marzo 2008ES 15:24:48 Vincent Bourdier escribió:
> > > > > > but if I want to get the world Matrix, the one which represent
> the
> > > > >
> > > > > node's
> > > > >
> > > > > > position and translation in absolute system, how can I do ?
> Which
> > > > > > matrix
> > > > >
> > > > > I
> > > > >
> > > > > > have to get ?
> > > > >
> > > > > If you have several wold matrices, it means that you have
> > > > > instantiated
> > >
> > > a
> > >
> > > > > node
> > > > > several times. Only you know in what instance you are interested.
> > >
> > > Think
> > >
> > > > > about
> > > > > the four wheels of a car, there are 4 instances of the same node,
> the
> > > > > wheel
> > > > > mesh.
> > > > >
>
>
>
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