Hi. What is the idea behind having a color in ShapeDrawable?
What this means, is that if you create a ShapeDrawable, and stitch a material in a node above it, you cannot control the color through a material when lighting is disabled. So if I would like to do: material = new osg::Material; stateset->setAttributeAndModes(material,osg::StateAttribute::OVERRIDE|osg::StateAttribute::ON); stateset->setMode(GL_LIGHTING,osg::StateAttribute::OVERRIDE|osg::StateAttribute::OFF|osg::StateAttribute::PROTECTED); material->setColorMode(osg::Material::OFF); // Diffuse color == glColor(diffuse); Then control the color of this node by changing the diffuse color: material->setDiffuse(osg::Material::FRONT_AND_BACK, osg::Vec4(1.0,0.0f,0.0f,1.0f)); It would render in white, due to that the ShapeDrawable applies a white color! Only way of changing this, would be to call ShapeDrawable::setColor() Is there another way of achieving this? (Except for skipping the use of ShapeDrawables completely). /Anders -- __________________________________________ Anders Backman, HPC2N 90187 Umeå University, Sweden and...@cs.umu.se http://www.hpc2n.umu.se Cell: +46-70-392 64 67
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