Hi Sebastian,
What do you mean by "reachable"? Deallocation doesn't mean the memory
is cleaned or something. So having a raw pointer to the deallocated
memory might give you the same data as long as no one is allocating
memory there.
I mean that after the first image is deleted, I still can use and
perform operations on the data through the second image. To rewrite my
question, I would like to know if data in an image is deallocated (and
so it is not safe to perform operations on it through the second image)
when it's shallow copied. I guess it is but I am not 100% sure.
Thank you,
Pierre-Jean
Cheers
Sebastian
Thanks for enlightening me,
Cheers,
Pierre-Jean
------------------
Read this topic online here:
http://forum.openscenegraph.org/viewtopic.php?p=68380#68380
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