On Wed, Feb 23, 2011 at 10:24 PM, Darren Addy <[email protected]> wrote:
> When you are talking about an object that is only 47 arc seconds wide > (at it's closest directly overhead) we would appear to be talking > about an 8 pixel wide image. (47 arcsec)*(0.500 m)/((5.48e-6m)*(206265 arcsec/radians)) = 20.7 pixels (Where 5.48 microns = K-x pixel pitch) -- PDML Pentax-Discuss Mail List [email protected] http://pdml.net/mailman/listinfo/pdml_pdml.net to UNSUBSCRIBE from the PDML, please visit the link directly above and follow the directions.
