Hi All,

I am dealing with a Buf what includes 32 bit integers, but
they are entered somewhat backwards as view with hexedit:

AE 5D 5C 72 represents the number 725C5DAE

This is what I have come up with to convert this type of
number in a buffer to and integer

$ p6 'my Buf $x=Buf.new(0xAE,0x5D,0x5C,0x72); my int32 $i=$x[3] +< 0x18 + $x[2] +< 0x10 + $x[1] +< 0x08 + $x[0]; say $x; say $i.base(0x10);'

Buf:0x<ae 5d 5c 72>

Is there a more "elegant" way to do this?

Many thanks,

Reply via email to