There's probably a nicer way but I don't generally play about with this sort of thing.
:16([~] $x.reverse.map( *.base(16) )) It does involve lots of String manipulation, as I say. There's probably a better way. On Fri, 8 Feb 2019 at 06:35, Todd Chester via perl6-users < perl6-users@perl.org> wrote: > Hi All, > > I am dealing with a Buf what includes 32 bit integers, but > they are entered somewhat backwards as view with hexedit: > > AE 5D 5C 72 represents the number 725C5DAE > > This is what I have come up with to convert this type of > number in a buffer to and integer > > $ p6 'my Buf $x=Buf.new(0xAE,0x5D,0x5C,0x72); my int32 $i=$x[3] +< 0x18 > + $x[2] +< 0x10 + $x[1] +< 0x08 + $x[0]; say $x; say $i.base(0x10);' > > Buf:0x<ae 5d 5c 72> > 725C5DAE > > > Is there a more "elegant" way to do this? > > Many thanks, > -T > -- Simon Proctor Cognoscite aliquid novum cotidie http://www.khanate.co.uk/
