Hi Jenn, The code looked ok to me , so I copied and pasted the code you posted and it worked for me.. Where are you getting the parsing error? Is it the whole code anyway?
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Gurhan -----Original Message----- From: Jennifer Downey [mailto:[EMAIL PROTECTED]] Sent: Thursday, February 21, 2002 9:33 AM To: [EMAIL PROTECTED] Subject: [PHP-DB] Parse error Can someone tell me why I am getting a parse error in this little snip? <? $origVar = 100; echo "<P>Original value is $origVar</p>"; $origVar += 25; echo "<P>Added a value, now it's $origVar</p>"; $origVar -= 12; echo "<P>Subtracted a value, now it's $origVar</p>"; $origVar .= " chickens"; echo "<P>Final answer: $origVar</p>"; ?> Thanks in advance Jen Downey -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
