mysql_fetch_array() brings back an associative array by default.

It's not "$result[0]" but instead "$results["column_name"]"

Also, you can use is_set() on subarrays.

if ((isset($result["col1"])) && 
     (is_array($result["col1"])) &&
     (sizeof($result["col1"])))
{
  // do stuff here
}

Remember that the above SEQUENCE is important.  If you deviate from it,
you may get "unknown variable" or other error messages.

-Szii

----- Original Message ----- 
From: "Prodoc" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Monday, April 22, 2002 2:38 PM
Subject: Re: [PHP-DB] Re: Retrieve information from mutiple tables


> 
> > 
> > Does the simple case (without specifying MainID) work?
> > 
> > And are you pretty sure that $row['MainID'] actually holds a valid value?
> > 
> > Have you tried printing the whole of the above query to see what it actually 
> > contains?
> > 
> > If it looks valid try copy-paste that query into the mysql command-line to 
> > see what comes up.
> > 
> 
> I tried the query in the mysql command-line and this does give me the 
> data I want to get.
> $row['MainID'] does hold a valid value is this should mean I doing 
> something wrong at displaying the values, doesn't it?
> I just started using mysql and php it will probebly be a stupid mistake 
> I made.
> I get one or more values back using the mysql command-line and I'm 
> trying to display the values one by one by using $result = 
> mysql_fetch_row (&res) (I tried mysql_fetch_array as well) but it only 
> displays one result by using $result[0].
> $result[1] or higher doesn't give me anything, what could be the problem?
> 
> 
> -- 
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