Try this:

$logit = mysql_query("INSERT INTO log (term,returns,time,date,ip) VALUES
('$search','$arrayword',CURTIME(), CURDATE(), '$ip'"));

Muhammed Mamedov

----- Original Message -----
From: "Axel IS Main" <[EMAIL PROTECTED]>
Sent: Thursday, February 26, 2004 11:05 AM
Subject: [PHP-DB] What's wrong with this query?

> I've just tried to do something I've done a thousand times. It does not
> work. I've checked all of the syntax, made sure the field and variable
> names are correct. No matter what I do it just doesn't work. The table
> remains empty. Here's the query:
> $logit = mysql_query("INSERT INTO log SET term='$search',
> returns='$arrayword', time=CURTIME(), date=CURDATE(), ip='$ip'");
> Now that doesn't look too difficult does it? Well, apparently it's
> impossible! I'm really hoping someone out there can see something that I
> missed.
> Nick
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